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X^2-300X+15000=0
a = 1; b = -300; c = +15000;
Δ = b2-4ac
Δ = -3002-4·1·15000
Δ = 30000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{30000}=\sqrt{10000*3}=\sqrt{10000}*\sqrt{3}=100\sqrt{3}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-100\sqrt{3}}{2*1}=\frac{300-100\sqrt{3}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+100\sqrt{3}}{2*1}=\frac{300+100\sqrt{3}}{2} $
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